Optimal. Leaf size=72 \[ \frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{b x^2-1}}\right )}{\sqrt{2} b^{3/2}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{b x^2-1}}\right )}{\sqrt{2} b^{3/2}} \]
[Out]
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Rubi [A] time = 0.091415, antiderivative size = 72, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.042 \[ \frac{\tan ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{b x^2-1}}\right )}{\sqrt{2} b^{3/2}}-\frac{\tanh ^{-1}\left (\frac{\sqrt{b} x}{\sqrt{2} \sqrt [4]{b x^2-1}}\right )}{\sqrt{2} b^{3/2}} \]
Antiderivative was successfully verified.
[In] Int[x^2/((-2 + b*x^2)*(-1 + b*x^2)^(3/4)),x]
[Out]
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Rubi in Sympy [A] time = 28.7619, size = 41, normalized size = 0.57 \[ \frac{x^{3} \sqrt [4]{b x^{2} - 1} \operatorname{appellf_{1}}{\left (\frac{3}{2},\frac{3}{4},1,\frac{5}{2},b x^{2},\frac{b x^{2}}{2} \right )}}{6 \sqrt [4]{- b x^{2} + 1}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**2/(b*x**2-2)/(b*x**2-1)**(3/4),x)
[Out]
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Mathematica [C] time = 0.297, size = 138, normalized size = 1.92 \[ \frac{10 x^3 F_1\left (\frac{3}{2};\frac{3}{4},1;\frac{5}{2};b x^2,\frac{b x^2}{2}\right )}{3 \left (b x^2-2\right ) \left (b x^2-1\right )^{3/4} \left (b x^2 \left (2 F_1\left (\frac{5}{2};\frac{3}{4},2;\frac{7}{2};b x^2,\frac{b x^2}{2}\right )+3 F_1\left (\frac{5}{2};\frac{7}{4},1;\frac{7}{2};b x^2,\frac{b x^2}{2}\right )\right )+10 F_1\left (\frac{3}{2};\frac{3}{4},1;\frac{5}{2};b x^2,\frac{b x^2}{2}\right )\right )} \]
Warning: Unable to verify antiderivative.
[In] Integrate[x^2/((-2 + b*x^2)*(-1 + b*x^2)^(3/4)),x]
[Out]
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Maple [F] time = 0.07, size = 0, normalized size = 0. \[ \int{\frac{{x}^{2}}{b{x}^{2}-2} \left ( b{x}^{2}-1 \right ) ^{-{\frac{3}{4}}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^2/(b*x^2-2)/(b*x^2-1)^(3/4),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{2}}{{\left (b x^{2} - 1\right )}^{\frac{3}{4}}{\left (b x^{2} - 2\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^2/((b*x^2 - 1)^(3/4)*(b*x^2 - 2)),x, algorithm="maxima")
[Out]
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Fricas [A] time = 0.234159, size = 1, normalized size = 0.01 \[ \left [-\frac{\sqrt{2}{\left (2 \, \arctan \left (\frac{\sqrt{2}{\left (b x^{2} - 1\right )}^{\frac{1}{4}}}{\sqrt{b} x}\right ) - \log \left (-\frac{\sqrt{2} b^{\frac{3}{2}} x^{2} - 4 \,{\left (b x^{2} - 1\right )}^{\frac{1}{4}} b x + 2 \, \sqrt{2} \sqrt{b x^{2} - 1} \sqrt{b}}{b x^{2} - 2 \, \sqrt{b x^{2} - 1}}\right )\right )}}{4 \, b^{\frac{3}{2}}}, -\frac{\sqrt{2}{\left (2 \, \arctan \left (\frac{\sqrt{2}{\left (b x^{2} - 1\right )}^{\frac{1}{4}} \sqrt{-b}}{b x}\right ) - \log \left (-\frac{\sqrt{2} \sqrt{-b} b x^{2} + 4 \,{\left (b x^{2} - 1\right )}^{\frac{1}{4}} b x - 2 \, \sqrt{2} \sqrt{b x^{2} - 1} \sqrt{-b}}{b x^{2} + 2 \, \sqrt{b x^{2} - 1}}\right )\right )}}{4 \, \sqrt{-b} b}\right ] \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^2/((b*x^2 - 1)^(3/4)*(b*x^2 - 2)),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{2}}{\left (b x^{2} - 2\right ) \left (b x^{2} - 1\right )^{\frac{3}{4}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**2/(b*x**2-2)/(b*x**2-1)**(3/4),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{2}}{{\left (b x^{2} - 1\right )}^{\frac{3}{4}}{\left (b x^{2} - 2\right )}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^2/((b*x^2 - 1)^(3/4)*(b*x^2 - 2)),x, algorithm="giac")
[Out]